Number of Transactions per Visit
In many e-commerce or banking applications, understanding user behavior is crucial. One key metric is how many transactions a user performs within a single "visit" to the platform. This challenge asks you to calculate this metric, helping to analyze user engagement and potential friction points.
Problem Description
You are given a list of transactions, each associated with a user ID and a timestamp. A "visit" for a user is defined as a contiguous sequence of transactions where the time difference between consecutive transactions is less than or equal to a specified session_timeout duration. Your task is to count the number of transactions that occur within each distinct visit for every user.
Key Requirements:
- For each user, identify all their distinct visits.
- For each identified visit, count the total number of transactions within that visit.
- Handle cases where a user has no transactions.
- Handle cases where transactions for a user are not ordered by timestamp.
Expected Behavior:
The output should be a data structure that maps each user ID to a list of counts. Each count in the list represents the number of transactions in a single visit for that user.
Edge Cases to Consider:
- A user with only one transaction.
- Transactions for a single user occurring very close together (within
session_timeout). - Transactions for a single user occurring far apart (exceeding
session_timeout). - An empty input list of transactions.
Examples
Example 1:
Input:
transactions = [
{"user_id": "user1", "timestamp": 1678886400}, # Visit 1 starts
{"user_id": "user2", "timestamp": 1678886410}, # Visit 1 starts
{"user_id": "user1", "timestamp": 1678886420}, # Still Visit 1 for user1
{"user_id": "user1", "timestamp": 1678886500}, # Visit 1 ends (difference > 60s)
{"user_id": "user1", "timestamp": 1678886530}, # Visit 2 starts
{"user_id": "user2", "timestamp": 1678886550}, # Visit 1 ends (difference > 60s)
{"user_id": "user2", "timestamp": 1678886580}, # Visit 2 starts
{"user_id": "user1", "timestamp": 1678886600}, # Still Visit 2 for user1
{"user_id": "user2", "timestamp": 1678886700} # Visit 2 ends (difference > 60s)
]
session_timeout = 60 # seconds
Output:
{
"user1": [2, 2],
"user2": [1, 1]
}
Explanation:
- user1:
- Transaction 1 (1678886400) and Transaction 3 (1678886420) are within 60s. Transaction 4 (1678886500) is > 60s from Transaction 3. So, Visit 1 has 2 transactions.
- Transaction 5 (1678886530) and Transaction 8 (1678886600) are within 60s. So, Visit 2 has 2 transactions.
- user2:
- Transaction 2 (1678886410) is within 60s of nothing before it. Transaction 6 (1678886550) is > 60s from Transaction 2. So, Visit 1 has 1 transaction.
- Transaction 7 (1678886580) is within 60s of nothing before it. Transaction 9 (1678886700) is > 60s from Transaction 7. So, Visit 2 has 1 transaction.
Example 2:
Input:
transactions = [
{"user_id": "userA", "timestamp": 100},
{"user_id": "userA", "timestamp": 110},
{"user_id": "userA", "timestamp": 120},
{"user_id": "userB", "timestamp": 150},
{"user_id": "userA", "timestamp": 200},
{"user_id": "userB", "timestamp": 210}
]
session_timeout = 30
Output:
{
"userA": [3, 1],
"userB": [1, 1]
}
Explanation:
- userA: The first three transactions are within 30s of each other. The fourth transaction is more than 30s after the third. So, the visits are [3, 1].
- userB: The two transactions are more than 30s apart. So, the visits are [1, 1].
Example 3: (Edge Case: Single Transaction)
Input:
transactions = [
{"user_id": "userX", "timestamp": 500}
]
session_timeout = 60
Output:
{
"userX": [1]
}
Explanation:
- userX has only one transaction, which constitutes a single visit of 1 transaction.
Example 4: (Edge Case: Empty Transactions)
Input:
transactions = []
session_timeout = 60
Output:
{}
Explanation:
- With no transactions, the output is an empty dictionary.
Constraints
- The number of transactions can range from 0 to 100,000.
user_idwill be a string.timestampwill be an integer representing Unix time (seconds since epoch).session_timeoutwill be a positive integer.- The solution should be efficient, aiming for a time complexity of O(N log N) or O(N) where N is the number of transactions.
Notes
- You will need to group transactions by
user_idfirst. - Within each user's transactions, ensure they are sorted by
timestampbefore processing visits. - Consider how to handle the very first transaction for any user when determining if it starts a new visit.
- The
session_timeoutdefines the maximum gap between consecutive transactions to be considered part of the same visit.