Linking Customer Orders: An INNER JOIN Challenge
You've been tasked with analyzing sales data by combining information from two separate tables: one containing customer details and another containing order information. The goal is to retrieve a consolidated view of orders, showing only those orders that are associated with existing customers. This is a fundamental operation in relational databases, crucial for understanding relationships between different data entities.
Problem Description
Your challenge is to write an SQL query that retrieves all columns from both the Customers table and the Orders table for all orders that have a matching customer in the Customers table. You need to use an INNER JOIN clause to achieve this.
Requirements:
- Retrieve all columns from both tables.
- Ensure that only orders with a corresponding customer in the
Customerstable are included in the result. - The join condition should be based on the common
CustomerIDcolumn present in both tables.
Expected Behavior:
The query should return rows where a CustomerID from the Orders table exists in the Customers table. If an order has a CustomerID that does not exist in the Customers table, that order should not appear in the output. Similarly, if a customer exists but has no orders, they will not appear in the output.
Edge Cases:
- Customers with no orders: These customers should not appear in the final result because they don't have any matching entries in the
Orderstable. - Orders with invalid CustomerIDs: Orders with
CustomerIDvalues that do not exist in theCustomerstable should not appear in the final result. - Empty tables: If either table is empty, the result of an
INNER JOINwill be an empty set.
Examples
Example 1:
Input Tables:
Customers table:
| CustomerID | CustomerName | |
|---|---|---|
| 1 | Alice Smith | alice@example.com |
| 2 | Bob Johnson | bob@example.com |
| 3 | Charlie Brown | charlie@test.com |
Orders table:
| OrderID | CustomerID | OrderDate | TotalAmount |
|---|---|---|---|
| 101 | 1 | 2023-10-26 | 150.00 |
| 102 | 2 | 2023-10-27 | 220.50 |
| 103 | 1 | 2023-10-27 | 75.25 |
| 104 | 4 | 2023-10-28 | 50.00 |
Output:
| OrderID | CustomerID | OrderDate | TotalAmount | CustomerID | CustomerName | |
|---|---|---|---|---|---|---|
| 101 | 1 | 2023-10-26 | 150.00 | 1 | Alice Smith | alice@example.com |
| 102 | 2 | 2023-10-27 | 220.50 | 2 | Bob Johnson | bob@example.com |
| 103 | 1 | 2023-10-27 | 75.25 | 1 | Alice Smith | alice@example.com |
Explanation:
The INNER JOIN successfully links orders to their respective customers. Order 104 is excluded because its CustomerID (4) does not exist in the Customers table. Charlie Brown is not included because he has no orders.
Example 2:
Input Tables:
Customers table:
| CustomerID | CustomerName | |
|---|---|---|
| 5 | David Lee | david@mail.net |
Orders table:
| OrderID | CustomerID | OrderDate | TotalAmount |
|---|---|---|---|
| 201 | 5 | 2023-11-01 | 300.00 |
| 202 | 5 | 2023-11-02 | 120.75 |
Output:
| OrderID | CustomerID | OrderDate | TotalAmount | CustomerID | CustomerName | |
|---|---|---|---|---|---|---|
| 201 | 5 | 2023-11-01 | 300.00 | 5 | David Lee | david@mail.net |
| 202 | 5 | 2023-11-02 | 120.75 | 5 | David Lee | david@mail.net |
Explanation:
Both orders have a valid CustomerID that exists in the Customers table, so both are included in the result.
Example 3: Edge Case - Empty Orders Table
Input Tables:
Customers table:
| CustomerID | CustomerName | |
|---|---|---|
| 1 | Alice Smith | alice@example.com |
Orders table:
(empty)
Output:
(empty result set)
Explanation:
An INNER JOIN requires matching records in both tables. Since there are no records in the Orders table, no matches can be found, resulting in an empty output.
Constraints
- The
Customerstable will have at least 0 rows and at most 1,000,000 rows. - The
Orderstable will have at least 0 rows and at most 5,000,000 rows. - The
CustomerIDcolumn in both tables is of an integer type. - The
CustomerIDcolumn is the primary key in theCustomerstable and a foreign key in theOrderstable (conceptually, for this problem). - The query should be efficient enough to run within a reasonable time frame for the given constraints.
Notes
- Pseudocode for the SQL query might look like:
SELECT * FROM table1 INNER JOIN table2 ON table1.column = table2.column; - Pay close attention to the table names and column names provided in the examples.
- Successfully completing this challenge demonstrates your understanding of how to combine data from related tables using
INNER JOIN, a foundational skill in SQL.