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Problems

Customer Order Summaries with LEFT JOIN

You are tasked with analyzing customer order data to understand which customers have placed orders and which ones haven't. This is crucial for marketing campaigns, identifying potential customers, and understanding overall engagement. You need to retrieve a summary of all customers and their associated order information, ensuring that even customers without any orders are included in the results.

Problem Description

The goal is to create a report that lists all customers from a Customers table and, for each customer, displays their order count from an Orders table. The report must include every customer, regardless of whether they have placed any orders. If a customer has not placed any orders, their order count should be represented as zero.

Key Requirements:

  • Retrieve all records from the Customers table.
  • For each customer, count the number of orders they have placed.
  • If a customer has no orders, their order count should be 0.
  • The output should contain at least the customer's identifier and their order count.

Expected Behavior:

The query should return a dataset where each row represents a customer. Each row will include the customer's unique identifier and the total number of orders associated with that customer.

Edge Cases:

  • Customers with zero orders should be present in the output.
  • The Orders table might contain orders from customers not present in the Customers table (though this scenario won't affect the output based on the requirement to list all customers).
  • Customers might have multiple orders.

Examples

Example 1:

Input Tables:

Customers Table:

customer_idcustomer_name
101Alice
102Bob
103Charlie

Orders Table:

order_idcustomer_idorder_date
50011012023-10-01
50021022023-10-02
50031012023-10-03

Output:

customer_idorder_count
1012
1021
1030

Explanation:

Alice (customer_id 101) has 2 orders. Bob (customer_id 102) has 1 order. Charlie (customer_id 103) has no orders in the Orders table, so their order_count is 0.

Example 2:

Input Tables:

Customers Table:

customer_idcustomer_name
201David
202Eve

Orders Table:

order_idcustomer_idorder_date
60012012023-11-15

Output:

customer_idorder_count
2011
2020

Explanation:

David (customer_id 201) has 1 order. Eve (customer_id 202) has no orders, resulting in an order_count of 0.

Example 3: Edge Case - Empty Orders Table

Input Tables:

Customers Table:

customer_idcustomer_name
301Frank
302Grace

Orders Table: (Empty)

Output:

customer_idorder_count
3010
3020

Explanation:

Since the Orders table is empty, no customers have any orders, so both Frank and Grace have an order_count of 0.

Constraints

  • The Customers table will have at least one record.
  • The Orders table may be empty.
  • customer_id is a unique identifier in both tables.
  • The join condition will always be Customers.customer_id = Orders.customer_id.
  • The query should be performant for tables with up to 1,000,000 records in each.

Notes

  • Consider how to handle the absence of matching orders for a customer.

  • You will need to aggregate the orders per customer.

  • The LEFT JOIN clause is essential for ensuring all customers are included.

  • The pseudocode for the SQL tables and operations is as follows:

    Tables:

    • Customers (customer_id INT PRIMARY KEY, customer_name VARCHAR)
    • Orders (order_id INT PRIMARY KEY, customer_id INT, order_date DATE)

    Operations:

    • SELECT: To specify the columns to retrieve.
    • FROM: To specify the primary table.
    • LEFT JOIN: To combine tables and include all rows from the left table.
    • ON: To specify the join condition.
    • GROUP BY: To group rows for aggregation.
    • COUNT(): An aggregate function to count the number of orders.
    • COALESCE() or IFNULL() (depending on SQL dialect) might be useful for handling NULLs, although COUNT on a joined column often handles this correctly when grouping.
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